Question

What is the concentration of silver(I) ion in a saturated solution of silver(I) carbonate containing 0.0024 M Na2CO3? For Ag2CO3, Ksp = 8.6 x 10^–12.

Answer 1

We address the equilibrium `Ag_2CO_3(s) rightleftharpoons2Ag^+ + CO_3^(2-)`

And so...`K_"sp"=[Ag^+]^2[CO_3^(2-)]`

Explanation:

And we have the data for this expression...

`K_"sp"=8.6xx10^-12=[Ag^+]^2[CO_3^(2-)]`

`[Ag^+]=sqrt(K_"sp"/[[CO_3^(2-)]])`

We are given that `[CO_3^(2-)]=0.0024*mol*L^-1`.

And so...`[Ag^+]=sqrt((8.6xx10^-12)/(0.0024))=5.99xx10^-5*mol*L^-1`....