What is the derivative of $1+tan^2x$ ?

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Answer 1 · 2016-02-05T20:53:47

$2tanxsec^2x$

differentiate using the $color(blue)(" chain rule ")$

rewrite $tan^2x = (tanx)^2$

$d/dx[ 1 + (tanx)^2] = 2(tanx) d/dx(tanx)$

$= 2tanxsec^2x$

What is the derivative of 1+tan^2x1+tan^2x?