Question

What is the derivative of `arcsin(3-x^2)`?

Answer 1

`(-2x)/sqrt(1-(3-x^2)^2)`

Explanation:

`f(x) = arcsin(3-x^2)`

`f'(x) = 1/sqrt(1-(3-x^2)^2) * d/dx (3-x^2)`
[Standard differential and Chain rule]

`= 1/sqrt(1-(3-x^2)^2) * (0-2x)`

`=(-2x)/sqrt(1-(3-x^2)^2)`