What is the derivative of #Arctan(sqrt(5x))#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer James May 7, 2018 the answer #d/dx[Arctan(sqrt(5x))]=[5/(2sqrt5x)]/[1+5x]=sqrt(5)/(2sqrt(x)*(5x+1))# Explanation: note that #d/dx[arctan(u)]=((du)/dx)/[1+u^2]# now let's derive #Arctan(sqrt(5x))# #d/dx[Arctan(sqrt(5x))]=[5/(2sqrt5x)]/[1+5x]=sqrt(5)/(2*sqrt(x)*(5*x+1))# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 3748 views around the world You can reuse this answer Creative Commons License