What is the derivative of #f(x)= 2^(3x)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases 1 Answer Manikandan S. Apr 7, 2015 Answer #d/dx(a^x) = a^xlog(a)# #f(t) = 2^t# where #t=3x# #(d(f(x)))/dx=d/dt(f(t))*dt/dx# #(d(f(x)))/dx = 2^tlog2*3# #f'(x) = 2^(3x) log2*3# Answer link Related questions How do I find #f'(x)# for #f(x)=5^x# ? How do I find #f'(x)# for #f(x)=3^-x# ? How do I find #f'(x)# for #f(x)=x^2*10^(2x)# ? How do I find #f'(x)# for #f(x)=4^sqrt(x)# ? What is the derivative of #f(x)=b^x# ? What is the derivative of 10^x? How do you find the derivative of #x^(2x)#? How do you find the derivative of #f(x)=pi^cosx#? How do you find the derivative of #y=(sinx)^(x^3)#? How do you find the derivative of #y=ln(1+e^(2x))#? See all questions in Differentiating Exponential Functions with Other Bases Impact of this question 1661 views around the world You can reuse this answer Creative Commons License