Question

What is the derivative of `f(x)=coshx`?

Answer 1

`\frac{d}{dx}(cosh(x))=sinh(x)`

Explanation:

Given `cosh(x)=\frac{e^x+e^(-x)}{2}`
Differentiating the right hand side of the equation with respect to `x`
`\frac{d}{dx}(e^x)+\frac{d}{dx}(e^{-x})=e^x-e^{-x}`
So we have `\frac{d}{dx}(cosh(x))=\frac{e^x-e^{-x}}{2}=sinh(x)`
So, that means the derivative of `cosh(x)` is `sinh(x)`