What is the derivative of #f(x)=e^cosx - cos(e^x)#?

1 Answer
Dec 24, 2015

Using the chain rule.

Explanation:

  • Chain rule states that #(dy)/(dx)=(dy)/(du)(du)/(dx)#

So, as for your function, you can think of each term separately, if you want, renaming #u=cosx# for the first and #v=e^x# for the second and apply the rule, which will end up giving you the following:

#(df(x))/g(x)=sinxe^(cosx)-e^xsin(e^x)#