What is the derivative of #f(x)=ln(x^2+x)# ? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer AJ Speller Sep 24, 2014 We find the derivative by using the chain rule. #f(x)=ln(x^2+x)# #f'(x)=1/(x^2+x)*(x^2+x)'# #f'(x)=1/(x^2+x)*(2x+1)# #f'(x)=(2x+1)/(x^2+x)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? What is the derivative of #f(x)=sin(ln(x))# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 18977 views around the world You can reuse this answer Creative Commons License