Question

What is the derivative of `f(x)=ln(x^2+x)` ?

Answer 1

We find the derivative by using the chain rule.

`f(x)=ln(x^2+x)`

`f'(x)=1/(x^2+x)*(x^2+x)'`

`f'(x)=1/(x^2+x)*(2x+1)`

`f'(x)=(2x+1)/(x^2+x)`