# What is the derivative of f(x)=ln(x^2+x) ?

$f \left(x\right) = \ln \left({x}^{2} + x\right)$
$f ' \left(x\right) = \frac{1}{{x}^{2} + x} \cdot \left({x}^{2} + x\right) '$
$f ' \left(x\right) = \frac{1}{{x}^{2} + x} \cdot \left(2 x + 1\right)$
$f ' \left(x\right) = \frac{2 x + 1}{{x}^{2} + x}$