What is the derivative of #f(x)=sin(-x+pi)-sin(x)#?
1 Answer
Dec 22, 2015
#0#
Explanation:
#sin(t+pi) = -sin(t)#
#sin(-t) = -sin(t)#
So:
#f(x) = sin(-x+pi)-sin(x) = -sin(-x)-sin(x)#
#= sin(x)-sin(x) = 0#
and
#d/(dx) 0 = 0#
