Question

What is the derivative of `sin(x/2)+cosx`?

Answer 1

`1/2cos(x/2)-sinx`

Explanation:

`"differentiate "sin(x/2)" using the "color(blue)"chain rule"`

`"given "y=f(g(x))" then"`

`dy/dx-f'(g(x))xxg'(x)larrcolor(blue)"chain rule"`

`rArrd/dx(sin(x/2)+cosx)`

`=cos(x/2)xxd/dx(1/2x)-sinx`

`=1/2cos(x/2)-sinx`