What is the derivative of #sin(x/2)+cosx#?
1 Answer
Feb 3, 2018
Explanation:
#"differentiate "sin(x/2)" using the "color(blue)"chain rule"#
#"given "y=f(g(x))" then"#
#dy/dx-f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#
#rArrd/dx(sin(x/2)+cosx)#
#=cos(x/2)xxd/dx(1/2x)-sinx#
#=1/2cos(x/2)-sinx#
