What is the derivative of #(sin(x))(Cos^2(x))#?

1 Answer
Jun 10, 2017

Never forget that #cos^2x = (cosx)^2#.

#y = sinxcos^2x#

is a product #y = uv#
Its derivative is #y' = u'v+uv'#

To differentiate #v = cos^2x#, we'll need the chain rule.
#d/dx(cos^2x) = 2cosx d/dx(cosx) = 2cosx(-sinx) = -2sinxcosx#

#y' = d/dx(sinxcos^2x) = (cosx)(cos^2x)+(sinx)(-2sinxcosx)#

# = cos^3x - 2sin^2xcosx#.

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