What is the derivative of #sinx - (1/3)sinx^3#?
1 Answer
Jun 23, 2018
Explanation:
#"differentiate "sinx^3" using the "color(blue)"chain rule"#
#"given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#
#d/dx(sinx^3)=cosx^3xxd/dx(x^3)=3x^2cosx^3#
#rArrd/dx(sinx-1/3sinx^3)#
#=cosx-1/3xx3x^2cosx^3#
#=cosx-x^2cosx^3#
