Question

What is the derivative of `tan^ -1(3x^2)`?

Answer 1

`(6x)/(1-9x^4)`

Explanation:

using the chain rule,
`d/(dx)(tan^(-1)(3x^2))`
`=1/(1-(3x^2)^2)*d/(dx)(3x^2)`
`=1/(1-9x^4)*3*2x`
`=(6x)/(1-9x^4)`