What is the derivative of $tan^-1(x^2)$ ?

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Answer 1 · 2016-01-17T10:34:43

$d/dx(tan^-1 (x^2))=(2x)/(1+x^4)$

the formula $d/dx(Tan ^-1 u)=1/(1+u^2)*(du)/dx$

Let $u=x^2$

$d/dx(Tan ^-1 x^2)=1/(1+(x^2)^2)*(d/dx(x^2))$

$d/dx(Tan ^-1 x^2)=(1/(1+(x^4))*2x)$

$d/dx(tan^-1 (x^2))=(2x)/(1+x^4)$

Just follow the formula

What is the derivative of tan^-1(x^2) tan^-1(x^2)?