What is the derivative of #tan(2x+1)#?

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Answer 1 · 2016-02-01T07:50:34

#(dy)/(dx) = 2 sec^2 (2x+1) #

As this is a function within a function, we will apply the Chain Rule.

We know the derivative of #tan x# and we know the derivative of #(ax+c)#, Then:

#(dy)/(dx) = d/(dx) tan(2x+1) #

#= sec^2 (2x+1) * d/(dx) (2x+1)#

#= sec^2 (2x+1) * 2#

#(dy)/(dx) = 2 sec^2 (2x+1) #

This will bet the derivative of the given function.