What is the derivative of $tan^2x$ ?

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Answer 1 · 2018-05-25T23:49:23

$(dy)/(dx)= 2tanxsec^2x$

Let $y=tan^2x$

Let $u=tanx$

$(du)/(dx)=sec^2x$

Since $y=tan^2x$

Then $y=u^2$

$(dy)/(du)=2u$

$(dy)/(dx)=(dy)/(du)times(du)/(dx)$

$(dy)/(dx)=2utimessec^2x$

$(dy)/(dx)=2tanxsec^2x$

What is the derivative of tan^2x tan^2x?