What is the derivative of #tan^3 (3x-1)#?
1 Answer
Feb 16, 2016
#9tan^2(3x-1)sec^2(3x-1)#
Explanation:
differentiate using the
#color(blue)(" chain rule") #
#d/dx[f(g(x))] = f'(g(x)).g'(x)# and
#d/dx(tanx) = sec^2x#
#d/dx(tan^3(3x-1)) = 3tan^2(3x-1) d/dx(tan(3x-1) d/dx(3x-1))#
#= 3tan^2(3x-1).sec^2(3x-1).3 = 9tan^2(3x-1)sec^2(3x-1)#
