What is the derivative of (tan(8x))^2? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Narad T. ยท Anjali G May 17, 2017 The derivative is =16tan(8x)sec^2(8x) Explanation: We need (u^n)'=n u^(n-1)* u' (tanx)'=sec^2x We calculate this derivative by the chain rule Let y=(tan(8x))^2 dy/dx=2tan(8x)*sec^2(8x)*8 =16tan(8x)sec^2(8x) Answer link Related questions What is the derivative of y=cos(x) ? What is the derivative of y=tan(x) ? How do you find the 108th derivative of y=cos(x) ? How do you find the derivative of y=cos(x) from first principle? How do you find the derivative of y=cos(x^2) ? How do you find the derivative of y=e^x cos(x) ? How do you find the derivative of y=x^cos(x)? How do you find the second derivative of y=cos(x^2) ? How do you find the 50th derivative of y=cos(x) ? How do you find the derivative of y=cos(x^2) ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 2738 views around the world You can reuse this answer Creative Commons License