What is the derivative of $tan (\sqrt{x})$ $tan(sqrtx)$ ?

Question

1406 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-11T15:03:26

$\frac{d}{d x} (tan (\sqrt{x}))$ $d/dx(tan(sqrtx))$

Chain rule:
$= ({sec}^{2} (\sqrt{x})) \cdot (\frac{1}{2 \sqrt{x}})$ $=(sec^2(sqrtx))*(1/(2sqrtx))$

$= \frac{{sec}^{2} (\sqrt{x})}{2 \sqrt{x}}$ $=[sec^2(sqrtx)]/[2sqrtx]$

What is the derivative of tan(sqrtx)tan(√x)tan(sqrtx)?