What is the derivative of #tanx^3#? Calculus Differentiating Trigonometric Functions Special Limits Involving sin(x), x, and tan(x) 1 Answer Konstantinos Michailidis Oct 11, 2015 The derivative is #3x^2*sec^2(x^3)# where #secx# is the secant function Explanation: The derivative is #d(tanx^3)/dx=d(x^3)/dx*1/cos^2(x^3)=3x^2*(1/cos^2(x^3))=3x^2*sec^2(x^3)# Answer link Related questions What are Special Limits Involving #y=sin(x)#? How do you find the limit #lim_(x->0)sin(x)/x# ? How do you find the limit #lim_(x->0)tan(x)/x# ? What is the derivative of #tanx/x#? How do you differentiate # g(x) =sin^2(x/6) #? How do you differentiate # g(x) =(1+cosx)/(1-cosx) #? What is the derivative of #tan(2x)#? How do you differentiate #f(x)=sinx/x#? How do you differentiate #f(x)=sinx/(1-cosx)#? How do you differentiate #f(x)=(x+2)/cosx#? See all questions in Special Limits Involving sin(x), x, and tan(x) Impact of this question 24229 views around the world You can reuse this answer Creative Commons License