What is the derivative of this function #y=29/4cot^-1((2x)/3)#?

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Answer 1 · 2018-05-13T11:32:22

the answer
#y'=-(58)/[12[1+((2x)/3)^2]]#

show below:

#y=cot^-1(x)#

#y'=[-1*x']/(1+(x)^2)#

#y=29/4cot^-1((2x)/3)#

#y'=29/4*-(2/3)/[1+((2x)/3)^2]#

#y'=-(58/12)/[1+((2x)/3)^2]#

#y'=-(58)/[12[1+((2x)/3)^2]]#