What is the derivative of this function #y=cos^-1(1-3x^2)#?

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Answer 1 · 2016-08-03T23:29:26

# = pm (6)/(sqrt( 6 - 9x^2)) #

#cos y = 1 - 3x^2#

#- sin y \ y' = -6x#

# y' = (6x)/(sin y )#

# = (6x)/(sqrt(1- cos^2 y) )#

# = (6x)/(sqrt(1- (1 - 3x^2)^2) )#

# = (6x)/(sqrt(1- (1 + 9x^4- 6 x^2)) )#

# = (6x)/(sqrt( - 9x^4+ 6 x^2)) #

# = (6x)/(sqrt( 6 x^2 - 9x^4)) #

# = pm (6)/(sqrt( 6 - 9x^2)) #