What is the derivative of this function #y=sin^-1(e^x)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Eddie Aug 12, 2016 # \ y' =(e^x)/sqrt(1 - e^(2x))# Explanation: #y=sin^-1(e^x)# #sin y= e^x# #cos y \ y' = e^x# # \ y' =(e^x)/cos y# # \ y' =(e^x)/sqrt(1 - sin^2 x)# # \ y' =(e^x)/sqrt(1 - (e^x)^2)# # \ y' =(e^x)/sqrt(1 - e^(2x))# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 20148 views around the world You can reuse this answer Creative Commons License