What is the derivative of this? y = t^(2) √(t-2)

1 Answer
Mar 8, 2018

Answer:

#dy/dx = 2tsqrt(t-2) + t^2/(2sqrt(t-2))#

Explanation:

By product rule, let #f(x)=t^2#, let #g(x)=sqrt(t-2)#

#d/dx f(x)*g(x)# = #f'(x)*g(x) + f(x)*g'(x)#

#f'(x) = 2t#, #g'(x) = 1/(2sqrt(t-2))#

Hence, #dy/dx = 2tsqrt(t-2) + t^2/(2sqrt(t-2))#