What is the derivative of #x * ((4-x^2)^(1/2))#? Calculus Basic Differentiation Rules Product Rule 1 Answer Somebody N. Dec 14, 2017 #-(2*(-2+x^2))/sqrt(4-x^2)# Explanation: Using the product rule: #f'(a*b)=b*f'(a)+a*f'(b)# Let #color(white)(88)a=x# Let #color(white)(88)b=(4-x^2)^(1/2)# #f'(a)=1# #f'(b)=1/2(4-x^2)^(-1/2)*-2x=-x(4-x^2)^(-1/2)# #f'(a*b)=(4-x^2)^(1/2) * 1+x * -x(4-x^2)^(-1/2)# #->=(4-x^2)^(1/2)+(-x^2)/(4-x^2)^(1/2)=-(2*(-2+x^2))/sqrt(4-x^2)# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 2748 views around the world You can reuse this answer Creative Commons License