What is the derivative of #x^(7x)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases 1 Answer Konstantinos Michailidis Jul 17, 2016 Rewrite this as #e^(7x*lnx)# Hence the derivative is #d(e^(7x*lnx))/dx=e^(7x*lnx)*[7*lnx+7x*1/x]=7*e^(7x*lnx)*[lnx+1]= 7*x^(7x)*(lnx+1)# Answer link Related questions How do I find #f'(x)# for #f(x)=5^x# ? How do I find #f'(x)# for #f(x)=3^-x# ? How do I find #f'(x)# for #f(x)=x^2*10^(2x)# ? How do I find #f'(x)# for #f(x)=4^sqrt(x)# ? What is the derivative of #f(x)=b^x# ? What is the derivative of 10^x? How do you find the derivative of #x^(2x)#? How do you find the derivative of #f(x)=pi^cosx#? How do you find the derivative of #y=(sinx)^(x^3)#? How do you find the derivative of #y=ln(1+e^(2x))#? See all questions in Differentiating Exponential Functions with Other Bases Impact of this question 5667 views around the world You can reuse this answer Creative Commons License