# What is the derivative of x sqrt(2x-3)?

$y ' = 1 \cdot \sqrt{2 x - 3} + x \cdot \frac{\cancel{2}}{\cancel{2} \sqrt{2 x - 3}} =$
$= \frac{2 x - 3 + x}{\sqrt{2 x - 3}} = \frac{3 \left(x - 1\right)}{\sqrt{2 x - 3}}$