What is the derivative of #y=sec^3(x)#?

1 Answer
Aug 6, 2014

#sec x# is equal to #1/cosx#.

Thus, #sec^3 x# is an equivalent statement to #1/(cosx)^3#.

And, we know that this is equivalent to #(cos x)^(-3)#.

So, all we need to do is use the power rule, keeping in mind to use the chain rule on #cos x#:

#dy/dx = -3*(cos x)^(-4) * d/dx[cos x]#

#= -3*(cos x)^(-4) * (-sinx)#

#= 3sinx(cos x)^(-4) #

#= (3sinx)/(cos^4 x) #