What is the derivative of #y = sin(tan 2x)#?
1 Answer
Feb 9, 2016
# dy/dx = 2cos(tan2x)sec^2 2x#
Explanation:
using the
#color(blue)(" chain rule ") #
# d/dxf(g(x)) = f'g(x). g'(x)#
# dy/dx = cos(tan2x) d/dx(tan2x)#
# = cos(tan2x)sec^2 2x . 2 #
# rArr dy/dx = 2cos(tan2x)sec^2 2x #
