What is the derivative of $y = sin(tan 2x)$ ?

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Answer 1 · 2016-02-09T11:26:42

$dy/dx = 2cos(tan2x)sec^2 2x$

using the $color(blue)(" chain rule ")$

$d/dxf(g(x)) = f'g(x). g'(x)$

$dy/dx = cos(tan2x) d/dx(tan2x)$

$>= cos(tan2x)sec^2 2x d/dx(2x)$

$= cos(tan2x)sec^2 2x . 2$

$rArr dy/dx = 2cos(tan2x)sec^2 2x$

What is the derivative of y = sin(tan 2x)y = sin(tan 2x)?