What is the Derivative of y=sin²x² ?
3 Answers
Explanation:
We know that,
Here,
Explanation:
"differentiate using the "color(blue)"chain rule"
"Given "y=f(g(x))" then"
dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"
y=sin^2x^2=(sinx^2)^2
rArrdy/dx=2sinx^2xxd/dx(sinx^2)
color(white)(rArrdy/dx)=2sinx^2xxcosx^2xxd/dx(x^2)
color(white)(rArrdy/dx)=4xsinx^2cosx^2=2xsin2x^2
Explanation:
Where:
Apply chain rule:
Therefore,
Using following identity: