Question

What is the derivative of y=sin x^2#?

Answer 1

`y'=cos(x^2)*2x=2xcos(x^2)`

Explanation:

This function is a composition of 2 functions: `f(x)=g(h(x))`, where:

`g(x)=sinx` and `h(x)=x^2`.

To calculate the derivative you use formula:

`f'(g(x))=f'(g(x))*g'(x)`