# What is the derivative of y=(sqrt(x))(x-1)?

$\frac{x - 1}{2 \sqrt{x}} + \sqrt{x}$
Applying product rule y'= $\left(x - 1\right) \frac{d}{\mathrm{dx}} \sqrt{x} + \sqrt{x} \frac{d}{\mathrm{dx}} \left(x - 1\right)$
=$\frac{x - 1}{2 \sqrt{x}} + \sqrt{x}$