What is the derivative of #y=tan^2(2x) #?

1 Answer
Jul 18, 2016

#4tan2xsec^2 2x#

Explanation:

Differentiate using the #color(blue)"chain rule combined with power rule"#

#color(orange)"Reminder - Chain rule"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(d/dx(f(g(x)))=f'(g(x))g'(x))color(white)(a/a)|))) ........ (A)#
#"----------------------------------------------------------"#

#f(g(x))=tan^2 2x=(tan2x)^2rArrf'(g(x))=2tan2x#

#g(x)=tan2xrArrg'(x)=sec^2 2x.d/dx(2x)=2sec^2 2x#
#"-----------------------------------------------------------"#
Substitute these values into (A)

#rArr2tan2x.2sec^2 2x#

#rArrdy/dx=4tan2xsec^2 2x#