What is the derivative of #y=tan(x)/x#?

1 Answer
Jul 23, 2014

This function, in the form of #y = f(x) = g(x)/(h(x))#, is a perfect candidate for using the quotient rule.

The quotient rule states that the derivative of #y# with respect to #x# can be solved with the following formula:

Quotient rule: #y'= f'(x) = (g'(x)h(x) - g(x)h'(x))/(h(x)^2)#

In this problem, we can assign the following values to the variables in the quotient rule:

#g(x) = tan(x)#
#h(x) = x#

#g'(x) = sec^2(x)#
#h'(x) = 1#

If we plug these values into the quotient rule, we get the final answer:

#y' = (sec^2(x) * x - tan(x) * 1)/x^2 = (xsec^2(x) - tan(x))/x^2#