What is the derivative of #y=xlnx#?

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Feb 3, 2015

The answer is: #y'=1*lnx+x*1/x=lnx+1#.

This is because the theorem of derivative of product says:

#y=f(x)*g(x)rArry'(x)=f'(x)*g(x)+f(x)*g'(x)#.

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