What is the difference in the boiling points of #O_2# and #O_3# at standard pressure in terms of intermolecular forces?

1 Answer
anor277
Feb 22, 2016

This site lists the boiling point of ozone as #-112# #""^@C.#

Explanation:

The normal boiling point of oxygen is #-183# #""^@C#, so the difference in volatility is quite substantial. Of course, ozone is a heavier molecule, with a bigger electron cloud, and consequently greater dispersion forces to increase intermolecular forces. However, the large difference in boiling point probably also reflects the polarity of the ozone molecule, the which we draw with formal positive and negative charges.

Related questions
See all questions in Vapor Pressure and Boiling
Impact of this question
7051 views around the world
You can reuse this answer
Creative Commons License