What is the discriminant of #5x^2 + 10x + 5 = 0#?

1 Answer
Dec 1, 2015

The discriminant is zero

Explanation:

By definition, the discriminant is simply #b^2-4ac#, where #a#, #b# and #c# are coefficients of

#ax^2+bx+c#

So, in your case, #a=c=5# and #b=10#. Plug that values in the definition to have

#b^2-4ac = 10^2 - 4*5*5 = 100-100=0#

A discriminant is zero when the parabola is a perfect square, and indeed this is the case, since

#(sqrt(5)x+sqrt(5))^2 = 5x^2 + 2*sqrt(5)x*sqrt(5)+5 = 5x^2+10x+5#