What is the distance between #(0, -5)# and #(18, -10)#?

1 Answer
Apr 6, 2018

#18.68# units (rounded to 2 decimal places)

Explanation:

Distance = #sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

ie:
#(x_1,y_1) = (0,-5)# and #(x_2,y_2) = (18,-10)#

Distance:
= #sqrt((0-18)^2+(-5+10)^2)#
= #sqrt(324+25)#
= #sqrt349#
= #18.68# units (rounded to 2 decimal places)