What is the distance between P(-3, -2) and Q(11, 0)?

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Answer 1 · 2018-06-20T16:29:47

$d = 10sqrt2$

The distance formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is:

$d = sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

Substituting in the points $(-3,-2)$ and $(11,0)$ :

$d = sqrt((11--3)^2+(0--2)^2)$

$d = sqrt(14^2+2^2)$

$d = sqrt(196+4)$

$d = sqrt(200)$

$d = 10sqrt2$