What is the domain and range of #y = x^2 + 1#?

1 Answer
Apr 23, 2018

Domain: #x in RR#
Range: #y>=1#

Explanation:

The key realization here is that we have a polynomial here, which is defined for all real numbers, thus our domain is

#x inRR#

To think about the range, let's think about what the zero of this polynomial is:

#x^2+1=0#

#=>x^2=-1#

Notice, we will be taking the square root of a negative number here, which is undefined for real numbers.

If we set #y# equal to #1#, #x# will be zero, and our answer will always be positive as the number we add to #x^2# increases. Thus, our range is

#y>=1#

Hope this helps!