What is the domain of #f(x)=secx#?

1 Answer
Oct 17, 2014

By rewriting a bit,

#f(x)=secx=1/cosx#.

Since the denominator cannot be zero, we need to exclude numbers that make #cosx# equal to zero.

Since for all integer #n#,

#cos(pi/2+npi)=cos({2n+1}/2pi)=0#,

the domain of #f# is all real numbers except for #x={2n+1}/2pi# for all integer #n#.


I hope that this was helpful.