What is the domain of #f(x)=sqrt(2x+5_#?

1 Answer
Bio
Feb 8, 2016

The largest possible domain is #[-5/2,oo)#.

Explanation:

The domain is defined by the function. There is nothing wrong with arbitrarily saying that the domain of #f# is #(7,8]#.

I'm assuming you are referring to the largest possible domain of #f#. Any domain of #f# must be a subset of the largest possible domain.

The square root only takes in non-negative input. Therefore,

#2x+5>=0#

#x>=-5/2#

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