What is the domain of the function: #x sqrt(9-x^2)#? Precalculus Functions Defined and Notation Domain 1 Answer BeeFree Jan 10, 2016 The argument of the square root function must be #>=0# Explanation: #9-x^2>=0# #-x^2>=-9# #x^2<=9# Domain : #-3<=x<=3# hope that helped Answer link Related questions What is the domain of a function? What are common mistakes students make when working with domain? How does the domain of a function relate to its x-values? What is the domain of a linear function? What is the domain of a quadratic function? What is the domain of a function like #f(x) = 5x^2#? What is the domain of #f(x) = {(1, 2), (3, 4), (5, 6), (7, 8), (9, 10), (10, 10)}#? What is the domain of #f(x) = x#? How do I find the domain of the function #f(x) = 2x#? How do I find the domain of the function #f(x)=5x^2+2x-1#? See all questions in Domain Impact of this question 2076 views around the world You can reuse this answer Creative Commons License