# What is the domain of the function: x sqrt(9-x^2)?

##### 1 Answer
Jan 10, 2016

The argument of the square root function must be $\ge 0$

#### Explanation:

$9 - {x}^{2} \ge 0$

$- {x}^{2} \ge - 9$

${x}^{2} \le 9$

Domain : $- 3 \le x \le 3$

hope that helped