# What is the empirical formula for the compound that is made of 1.85 moles of nitrogen and 4.63 moles of oxygen?

##### 1 Answer
Dec 20, 2016

Normalize the formula by dividing thru by the LOWEST molar quantity. We get ${N}_{2} {O}_{5}$ finally.

#### Explanation:

$\text{Relative number of moles of nitrogen:}$ $=$ $\frac{1.85 \cdot m o l}{1.85 \cdot m o l} = 1$.

$\text{Relative number of moles of oxygen:}$ $=$ $\frac{4.63 \cdot m o l}{1.85 \cdot m o l} = 2.5$.

Because, BY DEFINITION, $\text{the empiricial formula is the simplest}$ $\text{whole number ratio that defines constituent atoms in a species,}$ we double this ratio to get ${N}_{2} {O}_{5}$. Capisce?