What is the empirical formula for the compound which is comprised of 2.677 g Ba and 3.115 g Br?

1 Answer
Feb 27, 2016

BaBr_2

Explanation:

Masses:
Ba=2.677g
Br=3.115g

Atomic Masses:

Ba=137.327g/(mol)
Br=79.904g/(mol)

Looking for the values in mol:
Ba=2.677cancel(gBa) xx (1molBa)/(137.327cancel(gBa) = 0.01949molBa
Br=3.115cancel(gBr) xx (1molBr)/(79.904cancel(gBr)=0.038983molBr

Therefore:
Ba = (0.01949mol)/(0.01949mol)=1
Br=(0.03898mol)/(0.01949mol)=2

Empirical Formula=BaBr_2