Question

What is the empirical formula of a compound if it has 80g Ca and 70g Cl?

Answer 1

`CaCl`....

Explanation:

We determine the number of moles of calcium and chlorine respectively....

`"Moles of calcium"=(80*g)/(40.1*g*mol^-1)=2.0*mol`

`"Moles of chlorine"=(70*g)/(35.45*g*mol^-1)=2.0*mol`

We divide thru by the smallest molar quantity to get `CaCl`; a `Ca(+I)` salt that I don't think is known.