What is the empirical formula of a compound if it has 80g Ca and 70g Cl?

1 Answer
Aug 12, 2017

Answer:

#CaCl#....

Explanation:

We determine the number of moles of calcium and chlorine respectively....

#"Moles of calcium"=(80*g)/(40.1*g*mol^-1)=2.0*mol#

#"Moles of chlorine"=(70*g)/(35.45*g*mol^-1)=2.0*mol#

We divide thru by the smallest molar quantity to get #CaCl#; a #Ca(+I)# salt that I don't think is known.