# What is the empirical formula of a compound that contains 40% carbon, 6.7% hydrogen, and 53.3% oxygen?

Oct 21, 2015

$C {H}_{2} O$

#### Explanation:

To find the ratio in moles you divide by the ${A}_{r}$ of each element.

Using approximate values:

Ratio in grams $C : H : O \Rightarrow$

$40 : 6.7 : 53.3$

Ratio in moles $\Rightarrow$

$\frac{40}{12} : \frac{6.7}{1} : \frac{53.3}{16} \Rightarrow$

$3.33 : 6.7 : 3.33$

Dividing through by $3.33 \Rightarrow$

$1 : 2 : 1$

So the empirical formula is:

$C {H}_{2} O$