# What is the empirical formula of a compound that has a carbon-to-hydrogen ratio of 2 to 6?

$\text{6 H"/"2 C"xx"1/2"/"1/2" -> "3 H"/"1 C}$
Therefore, ${\text{C"_2"H}}_{6}$ reduces to $\setminus m a t h b f \left({\text{CH}}_{3}\right)$. This is not actually a very stable compound, but it's real.
A methyl radical has the structural formula $\cdot {\text{CH}}_{3}$ (so its carbon has one nonbonding valence electron). It is neutral.