What is the end behavior of the graph of #y = 2x^3 + 5x#?

1 Answer
Apr 2, 2016

#As to +-oo, y to +-oo#.

Explanation:

#y > or <0# according as #x > or < 0#. The graph is in the first and third quadrants.

#y(-x)=-y(x)#. The graph is symmetrical about the origin.

It passes though the origin, at which #d/dx(y) = 5, d^2/dx^2(y)=0#.
Origin is a point of inflexion and, here, the tangent reverses its sense of rotation.

There is no asymptote.