What is the energy of a photon of red light that has a frequency of #4.48 * 10^14# Hz?

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Answer 1 · 2015-12-04T04:18:11

#2.97xx10^-19# #"J"#

Use the formula #E=hv#.

#{(E="energy of photon"),(h="Planck constant"=6.626xx10^-34),(v="frequency of photon"):}#

We can plug in what we know:

#E=(6.626xx10^-34)(4.48xx10^14)#

Plug this into your calculator:

#E=2.97xx10^-19# #"J"#

Where energy #E# is measured in #"J"#, or joules.